A stationary body explodes into four identical fragments such that three of them fly off
mutually perpendicular to each other, each with same K.E., E 0 . The minimum energy of explosion will be :
A
6E 0
B
C
4E 0
D
8E 0
Text Solution
Verified by ExpertsThe correct answer is:
A
Using momentum conservation
K. E 1 = 
= E 0 + E 0 + E 0
Total energy = 3E 0 + E 0 + E 0 + E 0 = 6E 0
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